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0=25x^2+50x+25
We move all terms to the left:
0-(25x^2+50x+25)=0
We add all the numbers together, and all the variables
-(25x^2+50x+25)=0
We get rid of parentheses
-25x^2-50x-25=0
a = -25; b = -50; c = -25;
Δ = b2-4ac
Δ = -502-4·(-25)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{50}{-50}=-1$
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